NOMOR 3.
a. [tex] {5}^{ - 2} = \frac{1}{ {5}^{2} } = \frac{1}{25} [/tex]
b. [tex] {( \frac{2}{3}) }^{ - 3} = \frac{1}{ ({ \frac{2}{3} )}^{3} } = \frac{1}{( \frac{8}{27} )} = \frac{27}{8} [/tex]
NOMOR 4.
a. [tex]5( {x}^{2} - y)( { {x}^{2} - {y}^{2} })^{0} [/tex]
[tex] = 5 \times ( {x}^{2} - y) \times 1[/tex][tex] = 5( {x}^{2} - y) = 5 {x}^{2} - 5y[/tex]
b. [tex] \frac{(3x + 2y)}{ ({3x + 2y})^{0} } = \frac{(3x + 2y)}{1} = 3x + 2y[/tex]
NOMOR 5.
a. [tex] \frac{ {2}^{4} }{ {2}^{2} } = {2}^{4 - 2} = {2}^{2} = 4[/tex]
b. [tex] {p}^{2} \times {p}^{3} = {p}^{2 + 3} = {p}^{5} [/tex]
c. [tex] {( \frac{1}{2} )}^{3} = \frac{ {(1)}^{3} }{ {(2)}^{3} } = \frac{1 \times 1 \times 1}{2 \times 2 \times 2} = \frac{1}{8} [/tex]
d. [tex] {( \frac{ - 2}{3}) }^{2} = \frac{ {( - 2)}^{2} }{ {(3)}^{2} } = \frac{( - 2) \times ( - 2)}{3 \times 3} = \frac{4}{9} [/tex]
e. [tex] {( \frac{ - 2}{3}) }^{ - 2} = \frac{1}{ {( \frac{ - 2}{3}) }^{2} } = \frac{1}{ (\frac{( - 2) \times ( - 2)}{3 \times 3} )} = \frac{1}{( \frac{4}{9} )} = \frac{9}{4} [/tex]
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